storeperek%20erek%206183

88 Ranucleus emits a 4. ron pertalite hanya 86 60 MeV alpha particle 5 5% of the time when it decays to 222 86 Ra (a) (5 points) Calculate the Q value of this decay Solution: Alpha decay of 226 88 Ra: 226 88 Rn! 222 86 Po+ 4 2 He E = M m+ M Q = 222 4 + 222 Q = 4:60 MeV =) Q= 4:68 MeV Note: You can’t use the mass method as in 1(a) as you are given a speci c energy